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1122020999933 is a prime number
BaseRepresentation
bin10000010100111101101…
…010011100001011111101
310222021010120110110200212
4100110331222130023331
5121340344333444213
62215241020002205
7144030504065351
oct20247552341375
93867116413625
101122020999933
113a2934670199
12161556690365
1381a630a0852
143c43dd53461
151e2bdd7b9a8
hex1053da9c2fd

1122020999933 has 2 divisors, whose sum is σ = 1122020999934. Its totient is φ = 1122020999932.

The previous prime is 1122020999929. The next prime is 1122020999969. The reversal of 1122020999933 is 3399990202211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1075839849529 + 46181150404 = 1037227^2 + 214898^2 .

It is a cyclic number.

It is not a de Polignac number, because 1122020999933 - 22 = 1122020999929 is a prime.

It is a super-2 number, since 2×11220209999332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1122020999633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561010499966 + 561010499967.

It is an arithmetic number, because the mean of its divisors is an integer number (561010499967).

Almost surely, 21122020999933 is an apocalyptic number.

It is an amenable number.

1122020999933 is a deficient number, since it is larger than the sum of its proper divisors (1).

1122020999933 is an equidigital number, since it uses as much as digits as its factorization.

1122020999933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 472392, while the sum is 50.

The spelling of 1122020999933 in words is "one trillion, one hundred twenty-two billion, twenty million, nine hundred ninety-nine thousand, nine hundred thirty-three".