Base | Representation |
---|---|
bin | 10000010101000011000… |
… | …110000010101001000011 |
3 | 10222021100220220220212102 |
4 | 100111003012002221003 |
5 | 121341041200341121 |
6 | 2215254033021015 |
7 | 144032661441551 |
oct | 20250306025103 |
9 | 3867326826772 |
10 | 1122112121411 |
11 | 3a29810480a6 |
12 | 1615810b476b |
13 | 81a78c26098 |
14 | 3c44c0b2bd1 |
15 | 1e2c6d7a90b |
hex | 10543182a43 |
1122112121411 has 2 divisors, whose sum is σ = 1122112121412. Its totient is φ = 1122112121410.
The previous prime is 1122112121381. The next prime is 1122112121413. The reversal of 1122112121411 is 1141212112211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1122112121411 - 238 = 847234214467 is a prime.
It is a super-2 number, since 2×11221121214112 (a number of 25 digits) contains 22 as substring.
Together with 1122112121413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1122112121413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561056060705 + 561056060706.
It is an arithmetic number, because the mean of its divisors is an integer number (561056060706).
Almost surely, 21122112121411 is an apocalyptic number.
1122112121411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122112121411 is an equidigital number, since it uses as much as digits as its factorization.
1122112121411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64, while the sum is 20.
Adding to 1122112121411 its reverse (1141212112211), we get a palindrome (2263324233622).
The spelling of 1122112121411 in words is "one trillion, one hundred twenty-two billion, one hundred twelve million, one hundred twenty-one thousand, four hundred eleven".
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