Base | Representation |
---|---|
bin | 100001011100010… |
… | …0001011001011000 |
3 | 2220012110020210220 |
4 | 1002320201121120 |
5 | 4244230104422 |
6 | 303202440040 |
7 | 36543542541 |
oct | 10270413130 |
9 | 2805406726 |
10 | 1122113112 |
11 | 52644920a |
12 | 273963020 |
13 | 14b623b73 |
14 | a90574c8 |
15 | 687a2e5c |
hex | 42e21658 |
1122113112 has 32 divisors (see below), whose sum is σ = 2815212480. Its totient is φ = 372713760.
The previous prime is 1122113089. The next prime is 1122113123. The reversal of 1122113112 is 2113112211.
It is a super-2 number, since 2×11221131122 = 2518275672244649088, which contains 22 as substring.
It is a nude number because it is divisible by every one of its digits and also a Zuckerman number because it is divisible by the product of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 1122113091 and 1122113100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75814 + ... + 89397.
It is an arithmetic number, because the mean of its divisors is an integer number (87975390).
Almost surely, 21122113112 is an apocalyptic number.
1122113112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1122113112 is an abundant number, since it is smaller than the sum of its proper divisors (1693099368).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1122113112 is a wasteful number, since it uses less digits than its factorization.
1122113112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 165503 (or 165499 counting only the distinct ones).
The product of its digits is 24, while the sum is 15.
The square root of 1122113112 is about 33497.9568332160. The cubic root of 1122113112 is about 1039.1515244358.
Adding to 1122113112 its reverse (2113112211), we get a palindrome (3235225323).
Subtracting 1122113112 from its reverse (2113112211), we obtain a palindrome (990999099).
The spelling of 1122113112 in words is "one billion, one hundred twenty-two million, one hundred thirteen thousand, one hundred twelve".
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