Base | Representation |
---|---|
bin | 11001100000111011011101… |
… | …111111101011101100111111 |
3 | 112201022120001101110221121221 |
4 | 121200323131333223230333 |
5 | 104202003323222042421 |
6 | 1034354230205334211 |
7 | 32431124343346651 |
oct | 3140733577535477 |
9 | 481276041427557 |
10 | 112214040034111 |
11 | 32833786204654 |
12 | 107039bab67367 |
13 | 4a7c97a83ca92 |
14 | 1d9d28d40a6d1 |
15 | ce8e28554841 |
hex | 660eddfebb3f |
112214040034111 has 2 divisors, whose sum is σ = 112214040034112. Its totient is φ = 112214040034110.
The previous prime is 112214040034079. The next prime is 112214040034153. The reversal of 112214040034111 is 111430040412211.
It is a weak prime.
It is an emirp because it is prime and its reverse (111430040412211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112214040034111 - 25 = 112214040034079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112214040064111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56107020017055 + 56107020017056.
It is an arithmetic number, because the mean of its divisors is an integer number (56107020017056).
Almost surely, 2112214040034111 is an apocalyptic number.
112214040034111 is a deficient number, since it is larger than the sum of its proper divisors (1).
112214040034111 is an equidigital number, since it uses as much as digits as its factorization.
112214040034111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 112214040034111 its reverse (111430040412211), we get a palindrome (223644080446322).
The spelling of 112214040034111 in words is "one hundred twelve trillion, two hundred fourteen billion, forty million, thirty-four thousand, one hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •