Base | Representation |
---|---|
bin | 1010001101001101001101… |
… | …1000111010010101000111 |
3 | 1110201210221112220001100012 |
4 | 2203103103120322111013 |
5 | 2432330124240200403 |
6 | 35511152141340435 |
7 | 2235522435330323 |
oct | 243232330722507 |
9 | 43653845801305 |
10 | 11222001100103 |
11 | 3637251078272 |
12 | 1312a9556771b |
13 | 6352cb88bb51 |
14 | 2ab20d602983 |
15 | 146d9b3c7ed8 |
hex | a34d363a547 |
11222001100103 has 2 divisors, whose sum is σ = 11222001100104. Its totient is φ = 11222001100102.
The previous prime is 11222001100099. The next prime is 11222001100109. The reversal of 11222001100103 is 30100110022211.
11222001100103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11222001100103 - 22 = 11222001100099 is a prime.
It is a super-2 number, since 2×112220011001032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11222001100109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5611000550051 + 5611000550052.
It is an arithmetic number, because the mean of its divisors is an integer number (5611000550052).
Almost surely, 211222001100103 is an apocalyptic number.
11222001100103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11222001100103 is an equidigital number, since it uses as much as digits as its factorization.
11222001100103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 11222001100103 its reverse (30100110022211), we get a palindrome (41322111122314).
The spelling of 11222001100103 in words is "eleven trillion, two hundred twenty-two billion, one million, one hundred thousand, one hundred three".
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