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11222050055441 is a prime number
BaseRepresentation
bin1010001101001101011001…
…0011101010010100010001
31110201211001222000020102212
42203103112103222110101
52432330224303233231
635511201050521505
72235523601414261
oct243232623522421
943654058006385
1011222050055441
113637276775125
121312aa9a36295
13635308a6c8c4
142ab215d077a1
15146da084842b
hexa34d64ea511

11222050055441 has 2 divisors, whose sum is σ = 11222050055442. Its totient is φ = 11222050055440.

The previous prime is 11222050055413. The next prime is 11222050055443. The reversal of 11222050055441 is 14455005022211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11060972246416 + 161077809025 = 3325804^2 + 401345^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11222050055441 is a prime.

Together with 11222050055443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11222050055398 and 11222050055407.

It is not a weakly prime, because it can be changed into another prime (11222050055443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5611025027720 + 5611025027721.

It is an arithmetic number, because the mean of its divisors is an integer number (5611025027721).

Almost surely, 211222050055441 is an apocalyptic number.

It is an amenable number.

11222050055441 is a deficient number, since it is larger than the sum of its proper divisors (1).

11222050055441 is an equidigital number, since it uses as much as digits as its factorization.

11222050055441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16000, while the sum is 32.

Adding to 11222050055441 its reverse (14455005022211), we get a palindrome (25677055077652).

The spelling of 11222050055441 in words is "eleven trillion, two hundred twenty-two billion, fifty million, fifty-five thousand, four hundred forty-one".