Base | Representation |
---|---|
bin | 10000010101001010110… |
… | …010011111001011010011 |
3 | 10222021200220211110102112 |
4 | 100111022302133023103 |
5 | 121341322222310024 |
6 | 2215314523535535 |
7 | 144036116630354 |
oct | 20251262371323 |
9 | 3867626743375 |
10 | 1122241213139 |
11 | 3a2a379a9682 |
12 | 1615b838a5ab |
13 | 81a998b4317 |
14 | 3c4612b7d2b |
15 | 1e2d337a00e |
hex | 1054ac9f2d3 |
1122241213139 has 2 divisors, whose sum is σ = 1122241213140. Its totient is φ = 1122241213138.
The previous prime is 1122241213127. The next prime is 1122241213141. The reversal of 1122241213139 is 9313121422211.
It is a strong prime.
It is an emirp because it is prime and its reverse (9313121422211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1122241213139 - 228 = 1121972777683 is a prime.
It is a super-3 number, since 3×11222412131393 (a number of 37 digits) contains 333 as substring.
Together with 1122241213141, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1122241213339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561120606569 + 561120606570.
It is an arithmetic number, because the mean of its divisors is an integer number (561120606570).
Almost surely, 21122241213139 is an apocalyptic number.
1122241213139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122241213139 is an equidigital number, since it uses as much as digits as its factorization.
1122241213139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 32.
The spelling of 1122241213139 in words is "one trillion, one hundred twenty-two billion, two hundred forty-one million, two hundred thirteen thousand, one hundred thirty-nine".
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