11223100121 has 2 divisors, whose sum is σ = 11223100122. Its totient is φ = 11223100120.

The previous prime is 11223100093. The next prime is 11223100123. The reversal of 11223100121 is 12100132211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8605345225 + 2617754896 = 92765^2 + 51164^2 .

It is a cyclic number.

It is not a de Polignac number, because 11223100121 - 2¹⁴ = 11223083737 is a prime.

Together with 11223100123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11223100096 and 11223100105.

It is not a weakly prime, because it can be changed into another prime (11223100123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5611550060 + 5611550061.

It is an arithmetic number, because the mean of its divisors is an integer number (5611550061).

Almost surely, 2^11223100121 is an apocalyptic number.

It is an amenable number.

11223100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11223100121 is an equidigital number, since it uses as much as digits as its factorization.

11223100121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11223100121 its reverse (12100132211), we get a palindrome (23323232332).

The spelling of 11223100121 in words is "eleven billion, two hundred twenty-three million, one hundred thousand, one hundred twenty-one".