Base | Representation |
---|---|
bin | 10000010101010101011… |
… | …110000010111100110111 |
3 | 10222022011102000022002221 |
4 | 100111111132002330313 |
5 | 121342204110412043 |
6 | 2215344404343211 |
7 | 144043424005642 |
oct | 20252536027467 |
9 | 3868142008087 |
10 | 1122420404023 |
11 | 3a301a069416 |
12 | 1616483a4b07 |
13 | 81ac7a63b29 |
14 | 3c47b000a59 |
15 | 1e2e3e738ed |
hex | 10555782f37 |
1122420404023 has 2 divisors, whose sum is σ = 1122420404024. Its totient is φ = 1122420404022.
The previous prime is 1122420403903. The next prime is 1122420404041. The reversal of 1122420404023 is 3204040242211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1122420404023 is a prime.
It is a super-3 number, since 3×11224204040233 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1122420444023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561210202011 + 561210202012.
It is an arithmetic number, because the mean of its divisors is an integer number (561210202012).
Almost surely, 21122420404023 is an apocalyptic number.
1122420404023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122420404023 is an equidigital number, since it uses as much as digits as its factorization.
1122420404023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 1122420404023 its reverse (3204040242211), we get a palindrome (4326460646234).
The spelling of 1122420404023 in words is "one trillion, one hundred twenty-two billion, four hundred twenty million, four hundred four thousand, twenty-three".
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