Base | Representation |
---|---|
bin | 10000010101011011000… |
… | …001001100011011101111 |
3 | 10222022101220012021020121 |
4 | 100111123001030123233 |
5 | 121342401424111413 |
6 | 2215401532025411 |
7 | 144045634232254 |
oct | 20253301143357 |
9 | 3868356167217 |
10 | 1122513503983 |
11 | 3a3067677833 |
12 | 161673602267 |
13 | 81b1112ca71 |
14 | 3c48951742b |
15 | 1e2ec213b8d |
hex | 1055b04c6ef |
1122513503983 has 2 divisors, whose sum is σ = 1122513503984. Its totient is φ = 1122513503982.
The previous prime is 1122513503959. The next prime is 1122513504017. The reversal of 1122513503983 is 3893053152211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1122513503983 - 233 = 1113923569391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1122513513983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561256751991 + 561256751992.
It is an arithmetic number, because the mean of its divisors is an integer number (561256751992).
Almost surely, 21122513503983 is an apocalyptic number.
1122513503983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122513503983 is an equidigital number, since it uses as much as digits as its factorization.
1122513503983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 43.
The spelling of 1122513503983 in words is "one trillion, one hundred twenty-two billion, five hundred thirteen million, five hundred three thousand, nine hundred eighty-three".
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