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1122513504017 is a prime number
BaseRepresentation
bin10000010101011011000…
…001001100011100010001
310222022101220012021021212
4100111123001030130101
5121342401424112032
62215401532025505
7144045634232333
oct20253301143421
93868356167255
101122513504017
113a3067677864
12161673602295
1381b1112ca99
143c489517453
151e2ec213bb2
hex1055b04c711

1122513504017 has 2 divisors, whose sum is σ = 1122513504018. Its totient is φ = 1122513504016.

The previous prime is 1122513503983. The next prime is 1122513504029. The reversal of 1122513504017 is 7104053152211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1027042391761 + 95471112256 = 1013431^2 + 308984^2 .

It is a cyclic number.

It is not a de Polignac number, because 1122513504017 - 210 = 1122513502993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1122513504037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561256752008 + 561256752009.

It is an arithmetic number, because the mean of its divisors is an integer number (561256752009).

Almost surely, 21122513504017 is an apocalyptic number.

It is an amenable number.

1122513504017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1122513504017 is an equidigital number, since it uses as much as digits as its factorization.

1122513504017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8400, while the sum is 32.

Adding to 1122513504017 its reverse (7104053152211), we get a palindrome (8226566656228).

The spelling of 1122513504017 in words is "one trillion, one hundred twenty-two billion, five hundred thirteen million, five hundred four thousand, seventeen".