Base | Representation |
---|---|
bin | 10000010101011011000… |
… | …001001100011100010001 |
3 | 10222022101220012021021212 |
4 | 100111123001030130101 |
5 | 121342401424112032 |
6 | 2215401532025505 |
7 | 144045634232333 |
oct | 20253301143421 |
9 | 3868356167255 |
10 | 1122513504017 |
11 | 3a3067677864 |
12 | 161673602295 |
13 | 81b1112ca99 |
14 | 3c489517453 |
15 | 1e2ec213bb2 |
hex | 1055b04c711 |
1122513504017 has 2 divisors, whose sum is σ = 1122513504018. Its totient is φ = 1122513504016.
The previous prime is 1122513503983. The next prime is 1122513504029. The reversal of 1122513504017 is 7104053152211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1027042391761 + 95471112256 = 1013431^2 + 308984^2 .
It is a cyclic number.
It is not a de Polignac number, because 1122513504017 - 210 = 1122513502993 is a prime.
It is not a weakly prime, because it can be changed into another prime (1122513504037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561256752008 + 561256752009.
It is an arithmetic number, because the mean of its divisors is an integer number (561256752009).
Almost surely, 21122513504017 is an apocalyptic number.
It is an amenable number.
1122513504017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122513504017 is an equidigital number, since it uses as much as digits as its factorization.
1122513504017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 32.
Adding to 1122513504017 its reverse (7104053152211), we get a palindrome (8226566656228).
The spelling of 1122513504017 in words is "one trillion, one hundred twenty-two billion, five hundred thirteen million, five hundred four thousand, seventeen".
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