Base | Representation |
---|---|
bin | 11001100010001011100010… |
… | …110011101110010100101000 |
3 | 112201121202222111012102112000 |
4 | 121202023202303232110220 |
5 | 104204410420123143422 |
6 | 1034501530025251000 |
7 | 32440260121203462 |
oct | 3142134263562450 |
9 | 481552874172460 |
10 | 112300020131112 |
11 | 32867197788060 |
12 | 107185b5633a60 |
13 | 4a87b00892418 |
14 | 1da34c8493132 |
15 | ceb2aba28cac |
hex | 6622e2cee528 |
112300020131112 has 128 divisors (see below), whose sum is σ = 351280610611200. Its totient is φ = 32932557201600.
The previous prime is 112300020131087. The next prime is 112300020131119. The reversal of 112300020131112 is 211131020003211.
112300020131112 is a `hidden beast` number, since 112 + 30 + 0 + 0 + 201 + 311 + 12 = 666.
It is a super-2 number, since 2×1123000201311122 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (112300020131119) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 762254058 + ... + 762401369.
It is an arithmetic number, because the mean of its divisors is an integer number (2744379770400).
Almost surely, 2112300020131112 is an apocalyptic number.
112300020131112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
112300020131112 is an abundant number, since it is smaller than the sum of its proper divisors (238980590480088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112300020131112 is a wasteful number, since it uses less digits than its factorization.
112300020131112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1524655484 (or 1524655474 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 112300020131112 its reverse (211131020003211), we get a palindrome (323431040134323).
The spelling of 112300020131112 in words is "one hundred twelve trillion, three hundred billion, twenty million, one hundred thirty-one thousand, one hundred twelve".
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