11230042000061 has 2 divisors, whose sum is σ = 11230042000062. Its totient is φ = 11230042000060.

The previous prime is 11230041999997. The next prime is 11230042000063. The reversal of 11230042000061 is 16000024003211.

11230042000061 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9456430667161 + 1773611332900 = 3075131^2 + 1331770^2 .

It is a cyclic number.

It is not a de Polignac number, because 11230042000061 - 2⁶ = 11230041999997 is a prime.

It is a super-2 number, since 2×11230042000061² (a number of 27 digits) contains 22 as substring.

Together with 11230042000063, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11230041999997 and 11230042000042.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11230042000063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615021000030 + 5615021000031.

It is an arithmetic number, because the mean of its divisors is an integer number (5615021000031).

Almost surely, 2^{11230042000061} is an apocalyptic number.

It is an amenable number.

11230042000061 is a deficient number, since it is larger than the sum of its proper divisors (1).

11230042000061 is an equidigital number, since it uses as much as digits as its factorization.

11230042000061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11230042000061 its reverse (16000024003211), we get a palindrome (27230066003272).

The spelling of 11230042000061 in words is "eleven trillion, two hundred thirty billion, forty-two million, sixty-one", and thus it is an aban number.