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1123021314497 is a prime number
BaseRepresentation
bin10000010101111001010…
…010010101100111000001
310222100201021201201022102
4100111321102111213001
5121344421424030442
62215524152120145
7144064341446345
oct20257122254701
93870637651272
101123021314497
113a32a8289345
12161795696055
1381b923bac64
143c4d6b43625
151e32bac1232
hex105794959c1

1123021314497 has 2 divisors, whose sum is σ = 1123021314498. Its totient is φ = 1123021314496.

The previous prime is 1123021314431. The next prime is 1123021314511. The reversal of 1123021314497 is 7944131203211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1120879568656 + 2141745841 = 1058716^2 + 46279^2 .

It is a cyclic number.

It is not a de Polignac number, because 1123021314497 - 232 = 1118726347201 is a prime.

It is a super-2 number, since 2×11230213144972 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1123021314497.

It is not a weakly prime, because it can be changed into another prime (1123021314407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561510657248 + 561510657249.

It is an arithmetic number, because the mean of its divisors is an integer number (561510657249).

Almost surely, 21123021314497 is an apocalyptic number.

It is an amenable number.

1123021314497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123021314497 is an equidigital number, since it uses as much as digits as its factorization.

1123021314497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 38.

The spelling of 1123021314497 in words is "one trillion, one hundred twenty-three billion, twenty-one million, three hundred fourteen thousand, four hundred ninety-seven".