112341204104330 has 32 divisors (see below), whose sum is σ = 203676890497920. Its totient is φ = 44611457284800.

The previous prime is 112341204104329. The next prime is 112341204104347. The reversal of 112341204104330 is 33401402143211.

It is a super-2 number, since 2×112341204104330² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112341204104293 and 112341204104302.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34363880 + ... + 37490780.

It is an arithmetic number, because the mean of its divisors is an integer number (6364902828060).

Almost surely, 2^{112341204104330} is an apocalyptic number.

112341204104330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

112341204104330 is a deficient number, since it is larger than the sum of its proper divisors (91335686393590).

112341204104330 is a wasteful number, since it uses less digits than its factorization.

112341204104330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3152894.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 112341204104330 its reverse (33401402143211), we get a palindrome (145742606247541).

The spelling of 112341204104330 in words is "one hundred twelve trillion, three hundred forty-one billion, two hundred four million, one hundred four thousand, three hundred thirty".