Base | Representation |
---|---|
bin | 1010001101111010110011… |
… | …1100100011010001111111 |
3 | 1110202222112120111002012221 |
4 | 2203132230330203101333 |
5 | 2433030211201031333 |
6 | 35520534501510211 |
7 | 2236434652131016 |
oct | 243365474432177 |
9 | 43688476432187 |
10 | 11234241033343 |
11 | 3641462207279 |
12 | 1315330712367 |
13 | 6364cc64ccb3 |
14 | 2aba51039a7d |
15 | 147365c3ed2d |
hex | a37acf2347f |
11234241033343 has 2 divisors, whose sum is σ = 11234241033344. Its totient is φ = 11234241033342.
The previous prime is 11234241033287. The next prime is 11234241033347. The reversal of 11234241033343 is 34333014243211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11234241033343 - 217 = 11234240902271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11234241033299 and 11234241033308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11234241033347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617120516671 + 5617120516672.
It is an arithmetic number, because the mean of its divisors is an integer number (5617120516672).
Almost surely, 211234241033343 is an apocalyptic number.
11234241033343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234241033343 is an equidigital number, since it uses as much as digits as its factorization.
11234241033343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 11234241033343 its reverse (34333014243211), we get a palindrome (45567255276554).
The spelling of 11234241033343 in words is "eleven trillion, two hundred thirty-four billion, two hundred forty-one million, thirty-three thousand, three hundred forty-three".
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