1123436343611 has 2 divisors, whose sum is σ = 1123436343612. Its totient is φ = 1123436343610.

The previous prime is 1123436343599. The next prime is 1123436343613. The reversal of 1123436343611 is 1163436343211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1123436343611 is a prime.

Together with 1123436343613, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1123436343613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561718171805 + 561718171806.

It is an arithmetic number, because the mean of its divisors is an integer number (561718171806).

Almost surely, 2^{1123436343611} is an apocalyptic number.

1123436343611 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123436343611 is an equidigital number, since it uses as much as digits as its factorization.

1123436343611 is an evil number, because the sum of its binary digits is even.

The product of its digits is 93312, while the sum is 38.

The spelling of 1123436343611 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-six million, three hundred forty-three thousand, six hundred eleven".