1123440433 has 2 divisors, whose sum is σ = 1123440434. Its totient is φ = 1123440432.

The previous prime is 1123440431. The next prime is 1123440449. The reversal of 1123440433 is 3340443211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 649638144 + 473802289 = 25488^2 + 21767^2 .

It is a cyclic number.

It is not a de Polignac number, because 1123440433 - 2¹ = 1123440431 is a prime.

Together with 1123440431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1123440398 and 1123440407.

It is not a weakly prime, because it can be changed into another prime (1123440431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561720216 + 561720217.

It is an arithmetic number, because the mean of its divisors is an integer number (561720217).

Almost surely, 2^1123440433 is an apocalyptic number.

It is an amenable number.

1123440433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123440433 is an equidigital number, since it uses as much as digits as its factorization.

1123440433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 1123440433 is about 33517.7629474283. The cubic root of 1123440433 is about 1039.5610922238.

Adding to 1123440433 its reverse (3340443211), we get a palindrome (4463883644).

The spelling of 1123440433 in words is "one billion, one hundred twenty-three million, four hundred forty thousand, four hundred thirty-three".