Base | Representation |
---|---|
bin | 10000010110010010100… |
… | …010110011100000101111 |
3 | 10222101210211002022011111 |
4 | 100112102202303200233 |
5 | 121401303413433204 |
6 | 2220034210332451 |
7 | 144111005315023 |
oct | 20262242634057 |
9 | 3871724068144 |
10 | 1123445061679 |
11 | 3a34a54a3926 |
12 | 16189358a127 |
13 | 81c2c125435 |
14 | 3c53712a383 |
15 | 1e353dc5d04 |
hex | 105928b382f |
1123445061679 has 2 divisors, whose sum is σ = 1123445061680. Its totient is φ = 1123445061678.
The previous prime is 1123445061677. The next prime is 1123445061689. The reversal of 1123445061679 is 9761605443211.
It is a weak prime.
It is an emirp because it is prime and its reverse (9761605443211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1123445061679 - 21 = 1123445061677 is a prime.
It is a super-2 number, since 2×11234450616792 (a number of 25 digits) contains 22 as substring.
Together with 1123445061677, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123445061677) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561722530839 + 561722530840.
It is an arithmetic number, because the mean of its divisors is an integer number (561722530840).
Almost surely, 21123445061679 is an apocalyptic number.
1123445061679 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123445061679 is an equidigital number, since it uses as much as digits as its factorization.
1123445061679 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 49.
The spelling of 1123445061679 in words is "one trillion, one hundred twenty-three billion, four hundred forty-five million, sixty-one thousand, six hundred seventy-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •