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11234521352050 = 252224690427041
BaseRepresentation
bin1010001101111011110110…
…1001111000011101110010
31110210000021002221202012021
42203132331221320131302
52433031244431231200
635521022354022054
72236444624606513
oct243367551703562
943700232852167
1011234521352050
113641596468927
1213153aa57792a
13636545749759
142aba7a368a0a
1514738066241a
hexa37bda78772

11234521352050 has 12 divisors (see below), whose sum is σ = 20896209714906. Its totient is φ = 4493808540800.

The previous prime is 11234521351997. The next prime is 11234521352141. The reversal of 11234521352050 is 5025312543211.

It can be written as a sum of positive squares in 3 ways, for example, as 10843895102049 + 390626250001 = 3293007^2 + 625001^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11234521351997 and 11234521352015.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 112345213471 + ... + 112345213570.

Almost surely, 211234521352050 is an apocalyptic number.

11234521352050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11234521352050 is a deficient number, since it is larger than the sum of its proper divisors (9661688362856).

11234521352050 is a wasteful number, since it uses less digits than its factorization.

11234521352050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224690427053 (or 224690427048 counting only the distinct ones).

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 11234521352050 its reverse (5025312543211), we get a palindrome (16259833895261).

The spelling of 11234521352050 in words is "eleven trillion, two hundred thirty-four billion, five hundred twenty-one million, three hundred fifty-two thousand, fifty".

Divisors: 1 2 5 10 25 50 224690427041 449380854082 1123452135205 2246904270410 5617260676025 11234521352050