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1123652530813 is a prime number
BaseRepresentation
bin10000010110011110111…
…010001111001001111101
310222102100021110211022111
4100112132322033021331
5121402220021441223
62220110541214021
7144116104631221
oct20263672171175
93872307424274
101123652530813
113a35a161851a
12161930b61311
1381c630c6337
143c5568d4781
151e36720830d
hex1059ee8f27d

1123652530813 has 2 divisors, whose sum is σ = 1123652530814. Its totient is φ = 1123652530812.

The previous prime is 1123652530771. The next prime is 1123652530837. The reversal of 1123652530813 is 3180352563211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1123646640484 + 5890329 = 1060022^2 + 2427^2 .

It is a cyclic number.

It is not a de Polignac number, because 1123652530813 - 217 = 1123652399741 is a prime.

It is a super-3 number, since 3×11236525308133 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1123652530843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561826265406 + 561826265407.

It is an arithmetic number, because the mean of its divisors is an integer number (561826265407).

Almost surely, 21123652530813 is an apocalyptic number.

It is an amenable number.

1123652530813 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123652530813 is an equidigital number, since it uses as much as digits as its factorization.

1123652530813 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 40.

The spelling of 1123652530813 in words is "one trillion, one hundred twenty-three billion, six hundred fifty-two million, five hundred thirty thousand, eight hundred thirteen".