1123883153140 has 96 divisors (see below), whose sum is σ = 2613765458304. Its totient is φ = 402489077760.

The previous prime is 1123883153101. The next prime is 1123883153149. The reversal of 1123883153140 is 413513883211.

It is a super-2 number, since 2×1123883153140² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1123883153093 and 1123883153102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1123883153149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 96939184 + ... + 96950776.

It is an arithmetic number, because the mean of its divisors is an integer number (27226723524).

Almost surely, 2^{1123883153140} is an apocalyptic number.

1123883153140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1123883153140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1306882729152).

1123883153140 is an abundant number, since it is smaller than the sum of its proper divisors (1489882305164).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1123883153140 is a wasteful number, since it uses less digits than its factorization.

1123883153140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18257 (or 18255 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 40.

The spelling of 1123883153140 in words is "one trillion, one hundred twenty-three billion, eight hundred eighty-three million, one hundred fifty-three thousand, one hundred forty".