Base | Representation |
---|---|
bin | 10100111011111111… |
… | …01100011110010101 |
3 | 1002000101021102110222 |
4 | 22131333230132111 |
5 | 141010101422431 |
6 | 5055222124125 |
7 | 545360663111 |
oct | 123577543625 |
9 | 32011242428 |
10 | 11240654741 |
11 | 4849069308 |
12 | 2218580645 |
13 | 10a1a474c4 |
14 | 788c36741 |
15 | 45bc7957b |
hex | 29dfec795 |
11240654741 has 2 divisors, whose sum is σ = 11240654742. Its totient is φ = 11240654740.
The previous prime is 11240654701. The next prime is 11240654743. The reversal of 11240654741 is 14745604211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11216928100 + 23726641 = 105910^2 + 4871^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11240654741 is a prime.
Together with 11240654743, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11240654743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5620327370 + 5620327371.
It is an arithmetic number, because the mean of its divisors is an integer number (5620327371).
Almost surely, 211240654741 is an apocalyptic number.
It is an amenable number.
11240654741 is a deficient number, since it is larger than the sum of its proper divisors (1).
11240654741 is an equidigital number, since it uses as much as digits as its factorization.
11240654741 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 35.
The spelling of 11240654741 in words is "eleven billion, two hundred forty million, six hundred fifty-four thousand, seven hundred forty-one".
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