Base | Representation |
---|---|
bin | 1010001110010100110011… |
… | …1111000110100110110111 |
3 | 1110210122120000120100121012 |
4 | 2203211030333012212313 |
5 | 2433134010040233213 |
6 | 35524051243142435 |
7 | 2240102636102363 |
oct | 243451477064667 |
9 | 43718500510535 |
10 | 11241221024183 |
11 | 3644414234747 |
12 | 131675a214a1b |
13 | 63707276b5a7 |
14 | 2ac1140682a3 |
15 | 1476239054a8 |
hex | a394cfc69b7 |
11241221024183 has 2 divisors, whose sum is σ = 11241221024184. Its totient is φ = 11241221024182.
The previous prime is 11241221024179. The next prime is 11241221024269. The reversal of 11241221024183 is 38142012214211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11241221024183 - 22 = 11241221024179 is a prime.
It is a super-2 number, since 2×112412210241832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11241221024483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5620610512091 + 5620610512092.
It is an arithmetic number, because the mean of its divisors is an integer number (5620610512092).
Almost surely, 211241221024183 is an apocalyptic number.
11241221024183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11241221024183 is an equidigital number, since it uses as much as digits as its factorization.
11241221024183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 32.
Adding to 11241221024183 its reverse (38142012214211), we get a palindrome (49383233238394).
The spelling of 11241221024183 in words is "eleven trillion, two hundred forty-one billion, two hundred twenty-one million, twenty-four thousand, one hundred eighty-three".
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