Search a number
-
+
1124140130413 is a prime number
BaseRepresentation
bin10000010110111011111…
…110010010000001101101
310222110121020222110012221
4100112323332102001231
5121404214333133123
62220231200155341
7144134145310336
oct20267376220155
93873536873187
101124140130413
113a38218852a3
12161a48308b51
1382010129101
143c5a157d28d
151e394e2225d
hex105bbf9206d

1124140130413 has 2 divisors, whose sum is σ = 1124140130414. Its totient is φ = 1124140130412.

The previous prime is 1124140130369. The next prime is 1124140130431. The reversal of 1124140130413 is 3140310414211.

Together with next prime (1124140130431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 960396080004 + 163744050409 = 979998^2 + 404653^2 .

It is a cyclic number.

It is not a de Polignac number, because 1124140130413 - 221 = 1124138033261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1124140130453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562070065206 + 562070065207.

It is an arithmetic number, because the mean of its divisors is an integer number (562070065207).

Almost surely, 21124140130413 is an apocalyptic number.

It is an amenable number.

1124140130413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1124140130413 is an equidigital number, since it uses as much as digits as its factorization.

1124140130413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1124140130413 its reverse (3140310414211), we get a palindrome (4264450544624).

The spelling of 1124140130413 in words is "one trillion, one hundred twenty-four billion, one hundred forty million, one hundred thirty thousand, four hundred thirteen".