Base | Representation |
---|---|
bin | 10000010110111111101… |
… | …010110101111001011111 |
3 | 10222110202120200000221112 |
4 | 100112333222311321133 |
5 | 121404331222041302 |
6 | 2220241253252235 |
7 | 144135530360114 |
oct | 20267752657137 |
9 | 3873676600845 |
10 | 1124202143327 |
11 | 3a385389053a |
12 | 161a6503407b |
13 | 8201cc2c343 |
14 | 3c5a98c290b |
15 | 1e39a5c1552 |
hex | 105bfab5e5f |
1124202143327 has 2 divisors, whose sum is σ = 1124202143328. Its totient is φ = 1124202143326.
The previous prime is 1124202143303. The next prime is 1124202143341. The reversal of 1124202143327 is 7233412024211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1124202143327 - 212 = 1124202139231 is a prime.
It is a super-2 number, since 2×11242021433272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1124202143293 and 1124202143302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1124202143377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562101071663 + 562101071664.
It is an arithmetic number, because the mean of its divisors is an integer number (562101071664).
Almost surely, 21124202143327 is an apocalyptic number.
1124202143327 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124202143327 is an equidigital number, since it uses as much as digits as its factorization.
1124202143327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 1124202143327 its reverse (7233412024211), we get a palindrome (8357614167538).
The spelling of 1124202143327 in words is "one trillion, one hundred twenty-four billion, two hundred two million, one hundred forty-three thousand, three hundred twenty-seven".
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