Base | Representation |
---|---|
bin | 1010001110011100001011… |
… | …1101100100100100111100 |
3 | 1110210211122221222201102101 |
4 | 2203213002331210210330 |
5 | 2433202033241143030 |
6 | 35525015510434444 |
7 | 2240202662002345 |
oct | 243470275444474 |
9 | 43724587881371 |
10 | 11243200334140 |
11 | 364523a52a5a5 |
12 | 1317011062a24 |
13 | 6372c9850408 |
14 | 2ac260c990cc |
15 | 1476dc57c7ca |
hex | a39c2f6493c |
11243200334140 has 12 divisors (see below), whose sum is σ = 23610720701736. Its totient is φ = 4497280133648.
The previous prime is 11243200334117. The next prime is 11243200334143. The reversal of 11243200334140 is 4143300234211.
It is a happy number.
11243200334140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11243200334099 and 11243200334108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11243200334143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 281080008334 + ... + 281080008373.
It is an arithmetic number, because the mean of its divisors is an integer number (1967560058478).
Almost surely, 211243200334140 is an apocalyptic number.
11243200334140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11243200334140 is an abundant number, since it is smaller than the sum of its proper divisors (12367520367596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11243200334140 is a wasteful number, since it uses less digits than its factorization.
11243200334140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 562160016716 (or 562160016714 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 11243200334140 its reverse (4143300234211), we get a palindrome (15386500568351).
The spelling of 11243200334140 in words is "eleven trillion, two hundred forty-three billion, two hundred million, three hundred thirty-four thousand, one hundred forty".
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