Base | Representation |
---|---|
bin | 10100111100010011… |
… | …10010110011111101 |
3 | 1002000120020221000211 |
4 | 22132021302303331 |
5 | 141011241132031 |
6 | 5055354552421 |
7 | 545422330351 |
oct | 123611626375 |
9 | 32016227024 |
10 | 11243302141 |
11 | 484a607345 |
12 | 2219438711 |
13 | 10a2463506 |
14 | 789325461 |
15 | 45c0edbb1 |
hex | 29e272cfd |
11243302141 has 2 divisors, whose sum is σ = 11243302142. Its totient is φ = 11243302140.
The previous prime is 11243302139. The next prime is 11243302153. The reversal of 11243302141 is 14120334211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5707198116 + 5536104025 = 75546^2 + 74405^2 .
It is an emirp because it is prime and its reverse (14120334211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11243302141 - 21 = 11243302139 is a prime.
Together with 11243302139, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11243302111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621651070 + 5621651071.
It is an arithmetic number, because the mean of its divisors is an integer number (5621651071).
Almost surely, 211243302141 is an apocalyptic number.
It is an amenable number.
11243302141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11243302141 is an equidigital number, since it uses as much as digits as its factorization.
11243302141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 11243302141 its reverse (14120334211), we get a palindrome (25363636352).
The spelling of 11243302141 in words is "eleven billion, two hundred forty-three million, three hundred two thousand, one hundred forty-one".
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