Base | Representation |
---|---|
bin | 10000010111010000111… |
… | …001001010010111111111 |
3 | 10222111111201102001112201 |
4 | 100113100321022113333 |
5 | 121410424211004022 |
6 | 2220330055012331 |
7 | 144145636504165 |
oct | 20272071122777 |
9 | 3874451361481 |
10 | 1124491109887 |
11 | 3a3991a09382 |
12 | 161b2596a0a7 |
13 | 82067a66082 |
14 | 3c5d6023235 |
15 | 1e3b5b51127 |
hex | 105d0e4a5ff |
1124491109887 has 2 divisors, whose sum is σ = 1124491109888. Its totient is φ = 1124491109886.
The previous prime is 1124491109857. The next prime is 1124491109941. The reversal of 1124491109887 is 7889011944211.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1124491109887 - 227 = 1124356892159 is a prime.
It is a super-3 number, since 3×11244911098873 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1124491109857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562245554943 + 562245554944.
It is an arithmetic number, because the mean of its divisors is an integer number (562245554944).
Almost surely, 21124491109887 is an apocalyptic number.
1124491109887 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124491109887 is an equidigital number, since it uses as much as digits as its factorization.
1124491109887 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1161216, while the sum is 55.
The spelling of 1124491109887 in words is "one trillion, one hundred twenty-four billion, four hundred ninety-one million, one hundred nine thousand, eight hundred eighty-seven".
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