Base | Representation |
---|---|
bin | 1010001110100100000001… |
… | …0010101001111100001010 |
3 | 1110211001002111112212202000 |
4 | 2203221000102221330022 |
5 | 2433220340032410010 |
6 | 35530004302251430 |
7 | 2240306043324654 |
oct | 243510022517412 |
9 | 43731074485660 |
10 | 11245303013130 |
11 | 364611942842a |
12 | 13174b9286b76 |
13 | 637573368774 |
14 | 2ac3c02416d4 |
15 | 1477b1e737c0 |
hex | a3a404a9f0a |
11245303013130 has 32 divisors (see below), whose sum is σ = 29987474702400. Its totient is φ = 2998747470096.
The previous prime is 11245303013083. The next prime is 11245303013257. The reversal of 11245303013130 is 3131030354211.
11245303013130 is a `hidden beast` number, since 1 + 1 + 2 + 45 + 3 + 0 + 301 + 313 + 0 = 666.
It is a super-2 number, since 2×112453030131302 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11245303013094 and 11245303013103.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20824634940 + ... + 20824635479.
It is an arithmetic number, because the mean of its divisors is an integer number (937108584450).
Almost surely, 211245303013130 is an apocalyptic number.
11245303013130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11245303013130 is an abundant number, since it is smaller than the sum of its proper divisors (18742171689270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11245303013130 is a wasteful number, since it uses less digits than its factorization.
11245303013130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41649270435 (or 41649270429 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 27.
Adding to 11245303013130 its reverse (3131030354211), we get a palindrome (14376333367341).
The spelling of 11245303013130 in words is "eleven trillion, two hundred forty-five billion, three hundred three million, thirteen thousand, one hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •