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112517980997 is a prime number
BaseRepresentation
bin110100011001010011…
…0000010001101000101
3101202102120102122221112
41220302212002031011
53320414100342442
6123405014454405
711062205025632
oct1506246021505
9352376378845
10112517980997
114379a515544
1219982064405
13a7c20837a6
145635795189
152dd81c6082
hex1a32982345

112517980997 has 2 divisors, whose sum is σ = 112517980998. Its totient is φ = 112517980996.

The previous prime is 112517980931. The next prime is 112517980999. The reversal of 112517980997 is 799089715211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111929724481 + 588256516 = 334559^2 + 24254^2 .

It is an emirp because it is prime and its reverse (799089715211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112517980997 - 28 = 112517980741 is a prime.

It is a super-2 number, since 2×1125179809972 (a number of 23 digits) contains 22 as substring.

Together with 112517980999, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112517980999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56258990498 + 56258990499.

It is an arithmetic number, because the mean of its divisors is an integer number (56258990499).

Almost surely, 2112517980997 is an apocalyptic number.

It is an amenable number.

112517980997 is a deficient number, since it is larger than the sum of its proper divisors (1).

112517980997 is an equidigital number, since it uses as much as digits as its factorization.

112517980997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2857680, while the sum is 59.

The spelling of 112517980997 in words is "one hundred twelve billion, five hundred seventeen million, nine hundred eighty thousand, nine hundred ninety-seven".