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11253126002893 is a prime number
BaseRepresentation
bin1010001111000001001010…
…0100111111100011001101
31110211210021200212221020121
42203300102210333203031
52433332400224043033
635533340440144541
72241003644541205
oct243602244774315
943753250787217
1011253126002893
113649473295425
121318b21168151
1363821c0137a8
142ac9231cd405
15147abdb5662d
hexa3c1293f8cd

11253126002893 has 2 divisors, whose sum is σ = 11253126002894. Its totient is φ = 11253126002892.

The previous prime is 11253126002887. The next prime is 11253126002947. The reversal of 11253126002893 is 39820062135211.

It is a happy number.

11253126002893 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7321364463204 + 3931761539689 = 2705802^2 + 1982867^2 .

It is a cyclic number.

It is not a de Polignac number, because 11253126002893 - 25 = 11253126002861 is a prime.

It is a super-3 number, since 3×112531260028933 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11253126009893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5626563001446 + 5626563001447.

It is an arithmetic number, because the mean of its divisors is an integer number (5626563001447).

Almost surely, 211253126002893 is an apocalyptic number.

It is an amenable number.

11253126002893 is a deficient number, since it is larger than the sum of its proper divisors (1).

11253126002893 is an equidigital number, since it uses as much as digits as its factorization.

11253126002893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 43.

The spelling of 11253126002893 in words is "eleven trillion, two hundred fifty-three billion, one hundred twenty-six million, two thousand, eight hundred ninety-three".