11277504941 has 2 divisors, whose sum is σ = 11277504942. Its totient is φ = 11277504940.

The previous prime is 11277504893. The next prime is 11277504943. The reversal of 11277504941 is 14940577211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5841392041 + 5436112900 = 76429^2 + 73730^2 .

It is a cyclic number.

It is not a de Polignac number, because 11277504941 - 2¹⁰ = 11277503917 is a prime.

Together with 11277504943, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11277504943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5638752470 + 5638752471.

It is an arithmetic number, because the mean of its divisors is an integer number (5638752471).

Almost surely, 2^11277504941 is an apocalyptic number.

It is an amenable number.

11277504941 is a deficient number, since it is larger than the sum of its proper divisors (1).

11277504941 is an equidigital number, since it uses as much as digits as its factorization.

11277504941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 70560, while the sum is 41.

The spelling of 11277504941 in words is "eleven billion, two hundred seventy-seven million, five hundred four thousand, nine hundred forty-one".