Search a number
-
+
112811952437 is a prime number
BaseRepresentation
bin110100100010000011…
…1011100100100110101
3101210012001120221221122
41221010013130210311
53322014324434222
6123454115353325
711102404526342
oct1510407344465
9353161527848
10112811952437
1143930451648
1219a445b2845
13a83ac505a2
1456628397c9
152e03de3a42
hex1a441dc935

112811952437 has 2 divisors, whose sum is σ = 112811952438. Its totient is φ = 112811952436.

The previous prime is 112811952413. The next prime is 112811952481. The reversal of 112811952437 is 734259118211.

It is an a-pointer prime, because the next prime (112811952481) can be obtained adding 112811952437 to its sum of digits (44).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57903278161 + 54908674276 = 240631^2 + 234326^2 .

It is a cyclic number.

It is not a de Polignac number, because 112811952437 - 28 = 112811952181 is a prime.

It is a super-2 number, since 2×1128119524372 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112813952437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56405976218 + 56405976219.

It is an arithmetic number, because the mean of its divisors is an integer number (56405976219).

Almost surely, 2112811952437 is an apocalyptic number.

It is an amenable number.

112811952437 is a deficient number, since it is larger than the sum of its proper divisors (1).

112811952437 is an equidigital number, since it uses as much as digits as its factorization.

112811952437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120960, while the sum is 44.

The spelling of 112811952437 in words is "one hundred twelve billion, eight hundred eleven million, nine hundred fifty-two thousand, four hundred thirty-seven".