Base | Representation |
---|---|
bin | 10101000011000010… |
… | …01011100110010111 |
3 | 1002011111111112000011 |
4 | 22201201023212113 |
5 | 141120214432011 |
6 | 5105133101051 |
7 | 550006262131 |
oct | 124141134627 |
9 | 32144445004 |
10 | 11299764631 |
11 | 4879471461 |
12 | 2234327787 |
13 | 10b107227c |
14 | 792a22051 |
15 | 462053621 |
hex | 2a184b997 |
11299764631 has 2 divisors, whose sum is σ = 11299764632. Its totient is φ = 11299764630.
The previous prime is 11299764613. The next prime is 11299764649. The reversal of 11299764631 is 13646799211.
Together with previous prime (11299764613) it forms an Ormiston pair, because they use the same digits, order apart.
It is a balanced prime because it is at equal distance from previous prime (11299764613) and next prime (11299764649).
It is a cyclic number.
It is not a de Polignac number, because 11299764631 - 231 = 9152280983 is a prime.
It is a super-2 number, since 2×112997646312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11299764661) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5649882315 + 5649882316.
It is an arithmetic number, because the mean of its divisors is an integer number (5649882316).
Almost surely, 211299764631 is an apocalyptic number.
11299764631 is a deficient number, since it is larger than the sum of its proper divisors (1).
11299764631 is an equidigital number, since it uses as much as digits as its factorization.
11299764631 is an evil number, because the sum of its binary digits is even.
The product of its digits is 489888, while the sum is 49.
The spelling of 11299764631 in words is "eleven billion, two hundred ninety-nine million, seven hundred sixty-four thousand, six hundred thirty-one".
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