Base | Representation |
---|---|
bin | 1010010001110000001010… |
… | …1001010010010101100111 |
3 | 1111000021112122000120120221 |
4 | 2210130002221102111213 |
5 | 2440120102423130343 |
6 | 40011110143305211 |
7 | 2244256044343015 |
oct | 244340251222547 |
9 | 44007478016527 |
10 | 11300103333223 |
11 | 366738a813a71 |
12 | 13260518ab207 |
13 | 63c797792683 |
14 | 2b0cdc2d58b5 |
15 | 148e1ce7a5ed |
hex | a4702a52567 |
11300103333223 has 2 divisors, whose sum is σ = 11300103333224. Its totient is φ = 11300103333222.
The previous prime is 11300103333217. The next prime is 11300103333257. The reversal of 11300103333223 is 32233330100311.
It is a weak prime.
It is an emirp because it is prime and its reverse (32233330100311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11300103333223 - 213 = 11300103325031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11300103339223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650051666611 + 5650051666612.
It is an arithmetic number, because the mean of its divisors is an integer number (5650051666612).
Almost surely, 211300103333223 is an apocalyptic number.
11300103333223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300103333223 is an equidigital number, since it uses as much as digits as its factorization.
11300103333223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 11300103333223 its reverse (32233330100311), we get a palindrome (43533433433534).
The spelling of 11300103333223 in words is "eleven trillion, three hundred billion, one hundred three million, three hundred thirty-three thousand, two hundred twenty-three".
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