Base | Representation |
---|---|
bin | 1010010001110000100111… |
… | …0010010001111000000111 |
3 | 1111000021211222102221102221 |
4 | 2210130021302101320013 |
5 | 2440120324110144033 |
6 | 40011130103113211 |
7 | 2244262030533052 |
oct | 244341162217007 |
9 | 44007758387387 |
10 | 11300223131143 |
11 | 36674413a7a11 |
12 | 1326085a42807 |
13 | 63c7b654860b |
14 | 2b0d1019ba99 |
15 | 148e2874112d |
hex | a4709c91e07 |
11300223131143 has 2 divisors, whose sum is σ = 11300223131144. Its totient is φ = 11300223131142.
The previous prime is 11300223131077. The next prime is 11300223131173. The reversal of 11300223131143 is 34113132200311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11300223131143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11300223131173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650111565571 + 5650111565572.
It is an arithmetic number, because the mean of its divisors is an integer number (5650111565572).
Almost surely, 211300223131143 is an apocalyptic number.
11300223131143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300223131143 is an equidigital number, since it uses as much as digits as its factorization.
11300223131143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11300223131143 its reverse (34113132200311), we get a palindrome (45413355331454).
The spelling of 11300223131143 in words is "eleven trillion, three hundred billion, two hundred twenty-three million, one hundred thirty-one thousand, one hundred forty-three".
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