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11300341311331 is a prime number
BaseRepresentation
bin1010010001110001000011…
…0101000110011101100011
31111000022011012211010011221
42210130100311012131203
52440121044333430311
640011145524115511
72244264664204522
oct244342065063543
944008135733157
1011300341311331
1136674a2086496
1213260b9535b97
1363c804b86117
142b0d21b624b9
15148e33cd7671
hexa4710d46763

11300341311331 has 2 divisors, whose sum is σ = 11300341311332. Its totient is φ = 11300341311330.

The previous prime is 11300341311317. The next prime is 11300341311341. The reversal of 11300341311331 is 13311314300311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11300341311331 - 221 = 11300339214179 is a prime.

It is a super-2 number, since 2×113003413113312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11300341311296 and 11300341311305.

It is not a weakly prime, because it can be changed into another prime (11300341311341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650170655665 + 5650170655666.

It is an arithmetic number, because the mean of its divisors is an integer number (5650170655666).

Almost surely, 211300341311331 is an apocalyptic number.

11300341311331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300341311331 is an equidigital number, since it uses as much as digits as its factorization.

11300341311331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11300341311331 its reverse (13311314300311), we get a palindrome (24611655611642).

The spelling of 11300341311331 in words is "eleven trillion, three hundred billion, three hundred forty-one million, three hundred eleven thousand, three hundred thirty-one".