Base | Representation |
---|---|
bin | 1010010001110001000011… |
… | …0101000110011101100011 |
3 | 1111000022011012211010011221 |
4 | 2210130100311012131203 |
5 | 2440121044333430311 |
6 | 40011145524115511 |
7 | 2244264664204522 |
oct | 244342065063543 |
9 | 44008135733157 |
10 | 11300341311331 |
11 | 36674a2086496 |
12 | 13260b9535b97 |
13 | 63c804b86117 |
14 | 2b0d21b624b9 |
15 | 148e33cd7671 |
hex | a4710d46763 |
11300341311331 has 2 divisors, whose sum is σ = 11300341311332. Its totient is φ = 11300341311330.
The previous prime is 11300341311317. The next prime is 11300341311341. The reversal of 11300341311331 is 13311314300311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11300341311331 - 221 = 11300339214179 is a prime.
It is a super-2 number, since 2×113003413113312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11300341311296 and 11300341311305.
It is not a weakly prime, because it can be changed into another prime (11300341311341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650170655665 + 5650170655666.
It is an arithmetic number, because the mean of its divisors is an integer number (5650170655666).
Almost surely, 211300341311331 is an apocalyptic number.
11300341311331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300341311331 is an equidigital number, since it uses as much as digits as its factorization.
11300341311331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 11300341311331 its reverse (13311314300311), we get a palindrome (24611655611642).
The spelling of 11300341311331 in words is "eleven trillion, three hundred billion, three hundred forty-one million, three hundred eleven thousand, three hundred thirty-one".
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