11300413142230 has 8 divisors (see below), whose sum is σ = 20340743656032. Its totient is φ = 4520165256888.

The previous prime is 11300413142197. The next prime is 11300413142237. The reversal of 11300413142230 is 3224131400311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11300413142195 and 11300413142204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11300413142237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 565020657102 + ... + 565020657121.

It is an arithmetic number, because the mean of its divisors is an integer number (2542592957004).

Almost surely, 2^{11300413142230} is an apocalyptic number.

11300413142230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11300413142230 is a deficient number, since it is larger than the sum of its proper divisors (9040330513802).

11300413142230 is a wasteful number, since it uses less digits than its factorization.

11300413142230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1130041314230.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11300413142230 its reverse (3224131400311), we get a palindrome (14524544542541).

The spelling of 11300413142230 in words is "eleven trillion, three hundred billion, four hundred thirteen million, one hundred forty-two thousand, two hundred thirty".