11300433433 has 2 divisors, whose sum is σ = 11300433434. Its totient is φ = 11300433432.

The previous prime is 11300433367. The next prime is 11300433449. The reversal of 11300433433 is 33433400311.

It is a happy number.

11300433433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10364868864 + 935564569 = 101808^2 + 30587^2 .

It is a cyclic number.

It is not a de Polignac number, because 11300433433 - 2²¹ = 11298336281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11300433398 and 11300433407.

It is not a weakly prime, because it can be changed into another prime (11300433493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650216716 + 5650216717.

It is an arithmetic number, because the mean of its divisors is an integer number (5650216717).

Almost surely, 2^11300433433 is an apocalyptic number.

It is an amenable number.

11300433433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300433433 is an equidigital number, since it uses as much as digits as its factorization.

11300433433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 11300433433 its reverse (33433400311), we get a palindrome (44733833744).

The spelling of 11300433433 in words is "eleven billion, three hundred million, four hundred thirty-three thousand, four hundred thirty-three".