Base | Representation |
---|---|
bin | 110100100111110010… |
… | …1100101011001011111 |
3 | 101210200110201102111021 |
4 | 1221033211211121133 |
5 | 3322413111333041 |
6 | 123525152305011 |
7 | 11110232366515 |
oct | 1511745453137 |
9 | 353613642437 |
10 | 113004402271 |
11 | 43a1a047aa2 |
12 | 19a98b42167 |
13 | a86ba93127 |
14 | 56802144b5 |
15 | 2e15c5acd1 |
hex | 1a4f96565f |
113004402271 has 2 divisors, whose sum is σ = 113004402272. Its totient is φ = 113004402270.
The previous prime is 113004402239. The next prime is 113004402281. The reversal of 113004402271 is 172204400311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113004402271 - 25 = 113004402239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113004402281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56502201135 + 56502201136.
It is an arithmetic number, because the mean of its divisors is an integer number (56502201136).
Almost surely, 2113004402271 is an apocalyptic number.
113004402271 is a deficient number, since it is larger than the sum of its proper divisors (1).
113004402271 is an equidigital number, since it uses as much as digits as its factorization.
113004402271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 113004402271 its reverse (172204400311), we get a palindrome (285208802582).
The spelling of 113004402271 in words is "one hundred thirteen billion, four million, four hundred two thousand, two hundred seventy-one".
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