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11301031310119 is a prime number
BaseRepresentation
bin1010010001110011100111…
…1101001111001100100111
31111000100221022011200120121
42210130321331033030213
52440124003003410434
640011342213142411
72244321043123015
oct244347175171447
944010838150517
1011301031310119
113667816614821
12132627062aa07
1363c8b4b03225
142b0d896558b5
15148e746817b4
hexa4739f4f327

11301031310119 has 2 divisors, whose sum is σ = 11301031310120. Its totient is φ = 11301031310118.

The previous prime is 11301031310081. The next prime is 11301031310189. The reversal of 11301031310119 is 91101313010311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11301031310119 - 231 = 11298883826471 is a prime.

It is a super-2 number, since 2×113010313101192 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11301031310093 and 11301031310102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11301031310189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650515655059 + 5650515655060.

It is an arithmetic number, because the mean of its divisors is an integer number (5650515655060).

Almost surely, 211301031310119 is an apocalyptic number.

11301031310119 is a deficient number, since it is larger than the sum of its proper divisors (1).

11301031310119 is an equidigital number, since it uses as much as digits as its factorization.

11301031310119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 25.

The spelling of 11301031310119 in words is "eleven trillion, three hundred one billion, thirty-one million, three hundred ten thousand, one hundred nineteen".