1130104414132 has 6 divisors (see below), whose sum is σ = 1977682724738. Its totient is φ = 565052207064.

The previous prime is 1130104414079. The next prime is 1130104414151. The reversal of 1130104414132 is 2314144010311.

It can be written as a sum of positive squares in only one way, i.e., 1029745975696 + 100358438436 = 1014764^2 + 316794^2 .

It is a super-2 number, since 2×1130104414132² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1130104414097 and 1130104414106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 141263051763 + ... + 141263051770.

Almost surely, 2^{1130104414132} is an apocalyptic number.

It is an amenable number.

1130104414132 is a deficient number, since it is larger than the sum of its proper divisors (847578310606).

1130104414132 is a wasteful number, since it uses less digits than its factorization.

1130104414132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 282526103537 (or 282526103535 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1130104414132 its reverse (2314144010311), we get a palindrome (3444248424443).

The spelling of 1130104414132 in words is "one trillion, one hundred thirty billion, one hundred four million, four hundred fourteen thousand, one hundred thirty-two".