Base | Representation |
---|---|
bin | 10000011100100001001… |
… | …000101101011011110111 |
3 | 11000001001212100202001112 |
4 | 100130201020231123313 |
5 | 122004002334031411 |
6 | 2223101533545235 |
7 | 144435506210552 |
oct | 20344110553367 |
9 | 4001055322045 |
10 | 1130132330231 |
11 | 3a6317268753 |
12 | 16303b04521b |
13 | 827566c3688 |
14 | 3c9ad31b699 |
15 | 1e5e6018b8b |
hex | 1072122d6f7 |
1130132330231 has 2 divisors, whose sum is σ = 1130132330232. Its totient is φ = 1130132330230.
The previous prime is 1130132330203. The next prime is 1130132330269. The reversal of 1130132330231 is 1320332310311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1130132330231 is a prime.
It is a super-2 number, since 2×11301323302312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1130132330197 and 1130132330206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1130132330291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565066165115 + 565066165116.
It is an arithmetic number, because the mean of its divisors is an integer number (565066165116).
Almost surely, 21130132330231 is an apocalyptic number.
1130132330231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130132330231 is an equidigital number, since it uses as much as digits as its factorization.
1130132330231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1130132330231 its reverse (1320332310311), we get a palindrome (2450464640542).
The spelling of 1130132330231 in words is "one trillion, one hundred thirty billion, one hundred thirty-two million, three hundred thirty thousand, two hundred thirty-one".
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