Base | Representation |
---|---|
bin | 10000011100100001001… |
… | …011101010001110011001 |
3 | 11000001001220211000210121 |
4 | 100130201023222032121 |
5 | 122004003033303023 |
6 | 2223102002313241 |
7 | 144435515611201 |
oct | 20344113521631 |
9 | 4001056730717 |
10 | 1130133103513 |
11 | 3a6317746727 |
12 | 16303b358821 |
13 | 8275690463b |
14 | 3c9ad47d401 |
15 | 1e5e611cd5d |
hex | 107212ea399 |
1130133103513 has 2 divisors, whose sum is σ = 1130133103514. Its totient is φ = 1130133103512.
The previous prime is 1130133103511. The next prime is 1130133103553. The reversal of 1130133103513 is 3153013310311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1128772378969 + 1360724544 = 1062437^2 + 36888^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130133103513 - 21 = 1130133103511 is a prime.
Together with 1130133103511, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1130133103511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565066551756 + 565066551757.
It is an arithmetic number, because the mean of its divisors is an integer number (565066551757).
Almost surely, 21130133103513 is an apocalyptic number.
It is an amenable number.
1130133103513 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130133103513 is an equidigital number, since it uses as much as digits as its factorization.
1130133103513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1215, while the sum is 25.
Adding to 1130133103513 its reverse (3153013310311), we get a palindrome (4283146413824).
The spelling of 1130133103513 in words is "one trillion, one hundred thirty billion, one hundred thirty-three million, one hundred three thousand, five hundred thirteen".
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