Search a number
-
+
113020242019 is a prime number
BaseRepresentation
bin110100101000010001…
…0000000100001100011
3101210201120112011112121
41221100202000201203
53322431140221034
6123530520005111
711110514130526
oct1512042004143
9353646464477
10113020242019
1143a27a866a3
1219aa2300797
13a87214aa69
145682378bbd
152e173391b4
hex1a50880863

113020242019 has 2 divisors, whose sum is σ = 113020242020. Its totient is φ = 113020242018.

The previous prime is 113020242017. The next prime is 113020242059. The reversal of 113020242019 is 910242020311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113020242019 - 21 = 113020242017 is a prime.

It is a super-2 number, since 2×1130202420192 (a number of 23 digits) contains 22 as substring.

Together with 113020242017, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 113020241984 and 113020242002.

It is not a weakly prime, because it can be changed into another prime (113020242017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510121009 + 56510121010.

It is an arithmetic number, because the mean of its divisors is an integer number (56510121010).

Almost surely, 2113020242019 is an apocalyptic number.

113020242019 is a deficient number, since it is larger than the sum of its proper divisors (1).

113020242019 is an equidigital number, since it uses as much as digits as its factorization.

113020242019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

The spelling of 113020242019 in words is "one hundred thirteen billion, twenty million, two hundred forty-two thousand, nineteen".