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1130203232413 is a prime number
BaseRepresentation
bin10000011100100101010…
…111001011100010011101
311000001020210202221120021
4100130211113023202131
5122004124011414123
62223112545352141
7144440326652503
oct20344527134235
94001223687507
101130203232413
113a63532955a2
1216305a938651
13827682b9a28
143c9b88d6673
151e5ec371c5d
hex107255cb89d

1130203232413 has 2 divisors, whose sum is σ = 1130203232414. Its totient is φ = 1130203232412.

The previous prime is 1130203232399. The next prime is 1130203232441. The reversal of 1130203232413 is 3142323020311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1130166726649 + 36505764 = 1063093^2 + 6042^2 .

It is an emirp because it is prime and its reverse (3142323020311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1130203232413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130203232443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565101616206 + 565101616207.

It is an arithmetic number, because the mean of its divisors is an integer number (565101616207).

Almost surely, 21130203232413 is an apocalyptic number.

It is an amenable number.

1130203232413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130203232413 is an equidigital number, since it uses as much as digits as its factorization.

1130203232413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1130203232413 its reverse (3142323020311), we get a palindrome (4272526252724).

It can be divided in two parts, 113020 and 3232413, that added together give a palindrome (3345433).

The spelling of 1130203232413 in words is "one trillion, one hundred thirty billion, two hundred three million, two hundred thirty-two thousand, four hundred thirteen".