Base | Representation |
---|---|
bin | 110100101000010010… |
… | …1011010010101111111 |
3 | 101210201122012111101121 |
4 | 1221100211122111333 |
5 | 3322431402243312 |
6 | 123530551051411 |
7 | 11110524534622 |
oct | 1512045322577 |
9 | 353648174347 |
10 | 113021134207 |
11 | 43a28535a43 |
12 | 19aa2670b67 |
13 | a8723a0b97 |
14 | 568252bdb9 |
15 | 2e17463707 |
hex | 1a5095a57f |
113021134207 has 2 divisors, whose sum is σ = 113021134208. Its totient is φ = 113021134206.
The previous prime is 113021134199. The next prime is 113021134223. The reversal of 113021134207 is 702431120311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113021134207 - 23 = 113021134199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113021134907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510567103 + 56510567104.
It is an arithmetic number, because the mean of its divisors is an integer number (56510567104).
Almost surely, 2113021134207 is an apocalyptic number.
113021134207 is a deficient number, since it is larger than the sum of its proper divisors (1).
113021134207 is an equidigital number, since it uses as much as digits as its factorization.
113021134207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 113021134207 its reverse (702431120311), we get a palindrome (815452254518).
The spelling of 113021134207 in words is "one hundred thirteen billion, twenty-one million, one hundred thirty-four thousand, two hundred seven".
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