Base | Representation |
---|---|
bin | 10000011100100101110… |
… | …110011101111111001111 |
3 | 11000001021101012122122022 |
4 | 100130211312131333033 |
5 | 122004133111400242 |
6 | 2223113441240355 |
7 | 144440456453234 |
oct | 20344566357717 |
9 | 4001241178568 |
10 | 1130211434447 |
11 | 3a6357987937 |
12 | 1630616330bb |
13 | 82769bcc0c4 |
14 | 3c9b9a2d78b |
15 | 1e5ece420d2 |
hex | 10725d9dfcf |
1130211434447 has 2 divisors, whose sum is σ = 1130211434448. Its totient is φ = 1130211434446.
The previous prime is 1130211434411. The next prime is 1130211434533. The reversal of 1130211434447 is 7444341120311.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (7444341120311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1130211434447 - 212 = 1130211430351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1130211434047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565105717223 + 565105717224.
It is an arithmetic number, because the mean of its divisors is an integer number (565105717224).
Almost surely, 21130211434447 is an apocalyptic number.
1130211434447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130211434447 is an equidigital number, since it uses as much as digits as its factorization.
1130211434447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 1130211434447 its reverse (7444341120311), we get a palindrome (8574552554758).
The spelling of 1130211434447 in words is "one trillion, one hundred thirty billion, two hundred eleven million, four hundred thirty-four thousand, four hundred forty-seven".
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