Base | Representation |
---|---|
bin | 110100101000010011… |
… | …0000011100110000101 |
3 | 101210201122112002011121 |
4 | 1221100212003212011 |
5 | 3322431423200143 |
6 | 123530554433541 |
7 | 11110526140342 |
oct | 1512046034605 |
9 | 353648462147 |
10 | 113021303173 |
11 | 43a28640989 |
12 | 19aa27328b1 |
13 | a87242ca6c |
14 | 56825737c9 |
15 | 2e174987ed |
hex | 1a50983985 |
113021303173 has 2 divisors, whose sum is σ = 113021303174. Its totient is φ = 113021303172.
The previous prime is 113021303089. The next prime is 113021303249. The reversal of 113021303173 is 371303120311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71672927524 + 41348375649 = 267718^2 + 203343^2 .
It is a cyclic number.
It is not a de Polignac number, because 113021303173 - 229 = 112484432261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113021303573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510651586 + 56510651587.
It is an arithmetic number, because the mean of its divisors is an integer number (56510651587).
Almost surely, 2113021303173 is an apocalyptic number.
It is an amenable number.
113021303173 is a deficient number, since it is larger than the sum of its proper divisors (1).
113021303173 is an equidigital number, since it uses as much as digits as its factorization.
113021303173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 113021303173 its reverse (371303120311), we get a palindrome (484324423484).
The spelling of 113021303173 in words is "one hundred thirteen billion, twenty-one million, three hundred three thousand, one hundred seventy-three".
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